[SOLVED] Simple bash script

Issue

im new to bash scripting and tring to make a script

goal: reciving 2 names (1 - logfilename 2- program name) the program should compile the program

and send both outputs to a log

if success then write "compile V" and return 0 else compile X and return number

i tried

#!/bin/bash

gcc {$2}.c -Wall -g -o $2> $1 2>&1
exit

and i have no idea how to check if it did or didnt success and the to echo V or X

edit: thx for you guys, i got this

#!/bin/bash

gcc {$2}.c -Wall -g -o ${2}>${1} 2>&1

if (($?==0));then
    echo Compile V
[else
    echo compile X]
fi
exit

but all the if parts are still not working...

Solution

You can check exit status gcc like this:

#!/bin/bash

# execute gcc command
gcc "$2".c -Wall -g -o "$2"> "$1" 2>&1

# grab exit status of gcc
ret=$?

# write appropriate message as per return status value
((ret == 0)) && echo "compile V" || echo "compile X"

# return the exit status of gcc
exit $ret

Answered By - anubhava

Answer Checked By - Gilberto Lyons (WPSolving Admin)