[SOLVED] linux command to transform 'VW_ABCD_EF_GHIJ_KLM_...' into 'AbcdEfGhjKlm...'

Issue

I am trying to modify a string with the pattern 'VW_ABCD_EF_GHIJ_KLM_...' into 'AbcdEfGhjKlm...'

For example "s=VW_ABCD_EF_GHIJ_KLM" must become "AbcdEfGhjKlm".

So far I got s=VW_ABCD_EF_GHIJ_KLM; echo "${s,,}" | sed -e 's/vw\(.*\)/\1/g' which produces "_abcd_ef_ghij_klm".

I think I would have to create a variant number of groups for \(_.*\) and replace '_[a-z]' for '[A-Z]' in every group, but I could not find how to do it

Solution

Expanding on OP's current code to strip the _ and Uppercase the letter following the _:

$ s='VW_ABCD_EF_GHIJ_KLM'
$ sed -e 's/vw\(.*\)/\1/g;s/_\(.\)/\U\1/g' <<< "${s,,}"
AbcdEfGhijKlm

One equivalent while limiting the VW removal to the start of the string:

$ s='VW_ABCD_EF_GHIJ_KLM'
$ sed -E 's/^vw//g;s/_(.)/\U\1/g' <<< "${s,,}"
AbcdEfGhijKlm

NOTE: assumes each _ is followed by a letter (as in OP's example)

Answered By - markp-fuso

Answer Checked By - Robin (WPSolving Admin)