[SOLVED] How to show line number when executing bash script

Issue

I have a test script which has a lot of commands and will generate lots of output, I use set -x or set -v and set -e, so the script would stop when error occurs. However, it's still rather difficult for me to locate which line did the execution stop in order to locate the problem. Is there a method which can output the line number of the script before each line is executed? Or output the line number before the command exhibition generated by set -x? Or any method which can deal with my script line location problem would be a great help. Thanks.

Solution

You mention that you're already using -x. The variable PS4 denotes the value is the prompt printed before the command line is echoed when the -x option is set and defaults to : followed by space.

You can change PS4 to emit the LINENO (The line number in the script or shell function currently executing).

For example, if your script reads:

$ cat script
foo=10
echo ${foo}
echo $((2 + 2))

Executing it thus would print line numbers:

$ PS4='Line ${LINENO}: ' bash -x script
Line 1: foo=10
Line 2: echo 10
10
Line 3: echo 4
4

http://wiki.bash-hackers.org/scripting/debuggingtips (alternate: web archive link) gives the ultimate PS4 that would output everything you will possibly need for tracing:

export PS4='+(${BASH_SOURCE}:${LINENO}): ${FUNCNAME[0]:+${FUNCNAME[0]}(): }'

Answered By - devnull

Answer Checked By - Mary Flores (WPSolving Volunteer)