Issue
Struggling again.
I would like to add a line right after another one when matching some pattern and not a another one.
Here's my input file :
# abc def hello
# bye hello zzzz
# abc def hello
Expected output is :
# abc def hello
new line
# bye hello zzzz
# abc def hello
new line
I want to add a line after any line of a file that starts with #, contains the word hello but not bye
I read about some exclusion possibility with sed (i.e \*<kbd>/pattern/!</kbd> \*) but haven't managed to add it to command so far.
Thanks!
sed -e '/^#.\*hello.\*/Ia\\'"new line" $input_file
where can the /bye/! thingy be included to this?
Solution
where can the /bye/! thingy be included to this?
Sed is a programming language, technically. Start a block and check within.
The real issue is that a reads the whole next line. So you have to like start another one to close }.
sed -e '/^#.*hello.*/I{ /bye/!a\' -e "new line" -e '}' "$input_file"
The syntax of a command is:
a\
text
Technically, there has to be newline in the sed script for text. I see a\text works anyway, but technically it is not valid. GNU sed also allows for just a text.
Prefer to quote variable expansion in shell. Check your scripts with shellcheck.
Answered By - KamilCuk Answer Checked By - David Goodson (WPSolving Volunteer)