[SOLVED] Print lines after search of a pattern upto the end of the pattern

Issue

From the many hits about searching a pattern and printing the lines until the end of the pattern, I've encountered an issue. The solution works if there is no other entry that is similar or has the common numbers in the pattern. Let me explain.

startpat=30.202.10.0  
endpat=31.202.10.0

inputfile is as follows:

30.202.10.0  
abcd  
efgh

31.202.10.0  
ijkl  
mnop

130.202.10.0  
qrst  
uvwx

awk -v startpat="${startpat}" -v endpat="${endpat}" '$0 ~ startpat{ x = 1} $0 ~ endpat{ x = 0}x' inputfile  

I get the expected output. The problem arises when the data contains as an example 130.202.10.0. The result contains lines

abcd  
efgh  

qrst  
uvwx  

How do I get as follows

abcd  
efgh  

Solution

Current code:

$ awk -v startpat="${startpat}" -v endpat="${endpat}" '$0 ~ startpat{ x = 1} $0 ~ endpat{ x = 0}x' inputfile  
30.202.10.0
abcd
efgh

130.202.10.0
qrst
uvwx

Assuming the patterns (startpat and endpat) are not to be printed, and blank lines are not to be printed, one awk idea:

$ awk -v startpat="${startpat}" -v endpat="${endpat}" '$1==startpat {x=1;next} $1==endpat {x=0;next} x && NF>0' inputfile
abcd
efgh

Answered By - markp-fuso

Answer Checked By - Pedro (WPSolving Volunteer)