[SOLVED] How to use sed or awk in script to print numbers from line?

Issue

I have this line

"sha": "60dede389922f81a64ddb5f30ab6fe8a73deb643",

How to use sed or awk to print only 60dede389922f81a64ddb5f30ab6fe8a73deb643 ? I have use

awk '/sha/{print $1, $NF}' | sed 's/[^0-9]\{4\}//g'

But I have got wrong vaule

60389922f81a64ddb5f30ab6fe8a73deb643",

Solution

As far that now we know it's JSON:

xidel -e '($json).object.sha' https://api.github.com/repos/fairbird/Youtube-Opensource-DreamOS/git/refs/heads/master

See xidel

Or using curl and jq:

curl -Ls https://api.github.com/repos/fairbird/Youtube-Opensource-DreamOS/git/refs/heads/master |
    jq -r '.object.sha' 

Output:

e14845ed38a605fb8027e8f392581775c61125af

If it's not JSON:

What I would do:

awk -F'"' '/^"sha"/{print $4}' file

But I prefer this grep version:

grep -oP '^"sha":\s+"\K[[:xdigit:]]+' file

Answered By - Gilles Quénot

Answer Checked By - Gilberto Lyons (WPSolving Admin)