[SOLVED] How to filter results with sed using today's date

Issue

I'm asking because I can't find how to correctly use the sed function with the date function.

Context: I am concatenating log files into one with the cat function. So far so good. The date formats in the concatenated file might be: Feb 6, or 2022-02-07. I would like with the sed -i function to keep only the lines of the current date. I tried using the date function in the sed function:

• sed -i '/^$(date +%b)d/;/$(date +%d)/d' XYZ.log
• sed -i '/"$(date +%b)"/ from XYZ.log

I tried to use a variable in the sed function:

• MONTH=$(date '+%b')
• sed -i '/^"$MONTH"/ !d' XYZ.log

Both don't work.

Request: How to use the date function with the sed function in order to have in the XYZ.log file only the logs of the day?

Solution

The sed command is used to change text input; if you want to filter text you typically use the grep command, for instance like this:

grep "^$(date +%Y-%m-%d)" XYZ.log

Answered By - August Karlstrom

Answer Checked By - Robin (WPSolving Admin)