[SOLVED] shell script that print lines on a file based on conditions

Issue

I've a file like this

Name: Test1
Acronym: TEST11
Description: null
Toolkit: false
Tracks:

        List:
                Name: 1st_test
                Acronym: TEST11_1
                Created On: 2016-03-22 15:25:27.355
                Created By: User.9
                Is Default: false
                State: State[Inactive]
                Capability: Capability[Standard]
                No of running instances: 0

                Name: 2nd_test
                Acronym: TEST11_2
                Created On: 2016-03-23 15:07:18.955
                Created By: User.9
                Is Default: true
                State: State[Active]
                Capability: Capability[Standard]
                No of running instances: 0

                Name: 3rd_test
                Acronym: TEST11_3
                Created On: 2016-03-22 11:54:45.276
                Created By: User.9
                Is Default: false
                State: State[Inactive]
                Capability: Capability[Standard]
                No of running instances: 1

I need a script that prints Acronym (the one under List) if:

• line "Is Default" = false
• line "State" = Inactive
• line "No of running instances" = 0

From the example file provided I should expect only TEST11_1

Any help will be appreciated. Regards.

Solution

There are many ways to do this. One that comes to mind is to use grep to parse the file and then loop through each list segment.

Here's a complete example:

#!/usr/bin/env bash

shopt -s extglob

# name of the file
file=file.txt

# extract the "Name: ..." lines of file
list_names="$(grep -E '\s+Name' "$file")"

list=()

# add each "Name: ..." line to the "list" array
while IFS= read -r line; do
    # trim string
    list+=("${line##*( )}")
done <<< "$list_names"

# check if all three conditions are met
function check {
    grep --quiet --fixed-strings \
        'Is Default: false' <<< "$1" &&
    grep --quiet --fixed-strings \
        'State: State[Inactive]' <<< "$1" &&
    grep --quiet --fixed-strings \
        'No of running instances: 0' <<< "$1"
}

# loop through each list segment and check
# if conditions are met for each one
for f in "${list[@]}"; do
    # select and store all key/value pairs of each instance
    settings="$(grep -A 7 "$f" "$file")"
    # print "Acronym" value if all three strings
    # are found in the check function
    if check "$settings"; then
        output="$(grep 'Acronym' <<< "$settings")"
        # trim string
        echo "${output##*( )}"
    fi
done

The output of the script is Acronym: TEST11_1, because TEST11_1 meets all three conditions. The conditions are defined in the check function.

I'm not sure if this is clear enough, as the script became a bit verbose. If you have any questions, feel free to ask.

Answered By - dbran

Answer Checked By - David Marino (WPSolving Volunteer)