[SOLVED] passing file names to a script which takes multiple arguments which are modified names of the input file using xargs

Issue

I have a script that accepts two files as parameters (run_this file1 file2). I have bunch of files that I select with

ls analysis-{A,B,C}*-[123][abc].csv

and for each of those I also need to pass the corresponding file that only differs in name by prefix: instead of analysis, it starts with analysis_q. I tried many options I know but sed seems to refuse cooperation with xargs (and I know of no other simple way)

one of the things I tried:

ls analysis-{A,B,C}*-[123][abc].csv | xargs --interactive -I '{}' run_this `$(echo {} | sed 's/analysis/analysis_q/g')` {}

I am hoping to produce

run_this analysis_q-A-1a.csv analysis-A-1a.csv
run_this analysis_q-A-1b.csv analysis-A-1b.csv

and so forth.

Solution

Just a plain old loop.

for f1 in analysis-{A,B,C}*-[123][abc].csv; do
    f2=$(sed 's/analysis/analysis_q/g' <<<"$f1")
    run_this "$f1" "$f2"
done

For xargs, I would remove the prefix and use the variable part only.

printf "%s\n" analysis-{A,B,C}*-[123][abc].csv |
sed 's/^analysis-//' |
xargs --interactive -I {} run_this analysis-{} analysis_q-{}

Answered By - KamilCuk

Answer Checked By - Willingham (WPSolving Volunteer)