[SOLVED] find all the strings string with Dev_ and end with a number with 3 digits or less

Issue

I am trying to fit sed to my use case I have a list of string all starting with FP_ or DEV_ .... and ending with some numbers I need to find all the items where they start with Dev_ and ends with numbers of 3 digits or less so for example this one wont be accepted then

Dev_xxxxx-1111

but this is accepted and should be kept in the list

Dev_xxxxx-111

I am trying this

sed -e 's/  ",'${IMAGETAG}/Dev/

which gives me all the string starting with Dev and that fix half of the issue but cannot filter out and exclude the ones ends with more than 3 digits so here is what I need here is my input

[ "1.3.0.0-amd64", "Dev_04938095cc4bcefb1f85d7b306c1c49d335e80ce_167075", "Dev_08346f824a146dafbdca4b63eb3ce0b1549c6346_165", "Dev_0ab8997f5d45ed6b7515b5148d492c98109bf94a_16"] 

and output should be

[ "Dev_08346f824a146dafbdca4b63eb3ce0b1549c6346_165", "Dev_0ab8997f5d45ed6b7515b5148d492c98109bf94a_16"]

any help is appreciated

Solution

If your strings are for example in a file, you can use grep instead of sed to match the whole line using

grep -E "^(Fp|Dev)_(.*[^0-9])?[0-9]{1,3}$" file

See the regex matches here.

An example in bash matching anything between 2 underscores and ending with 1-3 digits:

#!/bin/bash

arr=("1.3.0.0-amd64" "Dev_04938095cc4bcefb1f85d7b306c1c49d335e80ce_167075" "Dev_08346f824a146dafbdca4b63eb3ce0b1549c6346_165" "Dev_0ab8997f5d45ed6b7515b5148d492c98109bf94a_16")

for i in "${arr[@]}"
do
   if [[ $i =~ ^(Fp|Dev)_.*_[0-9]{1,3}$ ]]; then
    echo "Match: $i"
else 
    echo "No match: $i"
fi
done

Output

No match: 1.3.0.0-amd64
No match: Dev_04938095cc4bcefb1f85d7b306c1c49d335e80ce_167075
Match: Dev_08346f824a146dafbdca4b63eb3ce0b1549c6346_165
Match: Dev_0ab8997f5d45ed6b7515b5148d492c98109bf94a_16

See the regex matches here.

Answered By - The fourth bird

Answer Checked By - Senaida (WPSolving Volunteer)