[SOLVED] Bash shell script did not pass the TRUE condition

Issue

While the condition did not pass in the TRUE result. What's wrong with the syntax?

RESULT="Exited (0) Less than a second ago"
if [ "$RESULT" = "Exited (0) Less than a second ago" || "$RESULT" = "Stop" ]
then
    echo 'exited'
elif [ "$RESULT" = *"Up"* ]
then
    echo 'stopped and exited'
else
    echo 'Docker already removed'
fi

Solution

The following script works properly based on the provided conditions.

#!/bin/sh

RESULT="Exited (0) Less than a second ago"


if [ "$RESULT" = "Exited (0) Less than a second ago" ] || [ "$RESULT" = "Stop" ]; then
    echo 'exited'
elif [ "$RESULT" = "Up" ]; then
    echo 'stopped and exited'
else
    echo 'Docker already removed'
fi

I changed the parameter "-o" to "[ ] || [ ]" after being informed by tjm3772 that the "-o" option is obsolete in POSIX 2017.

Answered By - cforler

Answer Checked By - Dawn Plyler (WPSolving Volunteer)