[SOLVED] how to specify a pattern which contains only certain characters a certain number of times

Issue

I work with pseudonymized data where pseudonyms are strings 9 characters long containing either letters a through f or numbers 0 through 9.

How can I make ls show only entries with such names? Would this also work with grep and find?

I know that I can specify a single character as [a-f,0-9], but how can I specify that such a character appears 9 times?

Solution

ls:

ls | grep -E '^[a-f0-9]{9}$'

find:

find /path/to/directory -type f -regex '.*/[a-f0-9]{9}$'

Answered By - TheAlphaGhost

Answer Checked By - Pedro (WPSolving Volunteer)