[SOLVED] How to extract pattern using sed and awk command?

Issue

I have a text message in a bash script which I am trying to extract a part of it within a pattern. For example my text string looks like:

(cert_a='aaa',cert_b='-----START\nabcdEFGHij\nKLMN\nO/PqR\n-----END\n')This is a sample text..

This is part of a script:

#!/bin/sh

test="(cert_a='aaa',cert_b='-----START\nabcdEFGHij\nKLMN\nO/PqR\n-----END\n')This is a sample text.."

sample_text=$test

echo $sample_text | busybox sed 's/cert_b='/cert_b='\\n/g' | awk "/-----START/,/-----END/"

This script will be executed by non-root user. It is working fine for root user.

Now I want to remove all \newline characters and extract only the string inside -----START,-----END. Hence my output should be:

-----START
abcdEFGHij
KLMN
O/PqR
-----END

Can anyone please let me know how to resolve this?

Thanks in advance

Solution

You need to first replace two characters \ n by a newline character.

text=$(cat <<EOF
-----START\nabcdEFGHij\nKLMN\nO/PqR\n-----END\n'This is a sample text..
EOF
)
echo "$text" | sed 's/\\n/\n/g' | awk "/-----START/,/-----END/"

Note: in your script, "\n" is just n. If you want to preserve \ , you have to write "\\n" or '\n' or use a here document as above.

Answered By - KamilCuk

Answer Checked By - Marie Seifert (WPSolving Admin)