[SOLVED] Get test number If the line above contains specific text

Issue

I have a junit file. How to get number from testIT?

If the line above contains the text "/system-err" or "/failure" then the test fails and writes to the file fail id test.

If the line above contains the text "/system-out" then the test is successful and writes to the passed file id test.

example "/system-err"

<system-err>Assertion Failure at Navigation.swift:88:Failed to get matching snapshot: No matches found for first query match sequence: `Descendants matching type NavigationBar`, given input App element pid: 21141 (no attribute values faulted in)</system-err>
    <system-out>testIT: C477997</system-out>

example "/failure"

>      <failure message='Assertion Failure at Element.swift:277:Failed to get matching snapshot: No matches found for Elements matching
> predicate &apos;&quot;One&quot; IN identifiers&apos; from input {(
>         Button, identifier: &apos;dictation&apos;, label: &apos;Диктовать&apos;, Disabled,
>         Button, label: &apos;Почему мне не приходит СМС?&apos;,
>         Button, label: &apos;Назад&apos;,
>         Button,
>         Button, label: &apos;Продолжить&apos;
>     )}'>
>         </failure>
>         <system-out>testIT: C478067</system-out>

passed test

<system-out>      Setting up automation session</system-out>
    <system-out>testIT: C478057</system-out>

fail file contains id

477997
478067

passed file contains id

478057

I tried

xmllint  $1 | awk -F'testIT: C|, | \\(' '/testIT:/{print $2"\n"$4"\n"$6}'| awk 'NF!=0' | sort| uniq|  2>/dev/null > successfullCases.xml

but I get

470836</system-out>
477975</system-out>
477997</system-out>
478057</system-out>
478067</system-out>
478098</system-out>

Full file https://disk.yandex.ru/d/DhdlvwfYj4J00A

Solution

Let's try this:

arr=(`grep -En "C[0-9]{6}" $1 | cut -d":" -f 1 | xargs`)


>fail.out
>err.out
>pass.out

for i in ${!arr[@]}; do
    line_num="${arr[$i]}"
    if head -$line_num $1 | tail -2 | grep -q "/system-err"
    then
        echo -ne "$i) Line: $line_num\t\tError\t\tID: "
        head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}'
        head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}' >> err.out
        #--------------------------------------------------------
    elif head -$line_num $1 | tail -2 | grep -q "/failure"
    then
        echo -ne "$i) Line: $line_num\t\tFailure\t\tID: "
        head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}'
        head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}' >> fail.out
        # ----------------------------------------------------------
    elif head -$line_num $1 | tail -2 | grep -q "/system-out"
    then
        echo -ne "$i) Line: $line_num\t\tPass\t\tID: "
        head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}'
        head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}' >> pass.out
        # ----------------------------------------------------------
    fi
done

Save the script in a file and try to run it in this way:

[user@host]# bash script.sh report.junit

Answered By - sinuxnet

Answer Checked By - David Goodson (WPSolving Volunteer)