[SOLVED] PYTHON - grep command: wrong output, exit status 2

Issue

I trying to find a Pattern in specific large files (GB) in subfolders

I am runnging Python code.

1. tried....

FILE_PATH=/folder1/FILE.txt - OK, absolute path

with open (FILE_PATH, "r") as FILE:
  for index, x in enumerate(FILE):
    if re.findall(".*TEXT.*", x):
      ...takes too much time...

2. another way

in Bash from terminal:

grep -a 'TEXT' /folder1/FILE.txt - output OK as desired

Python code:

FILE_PATH=/folder1/FILE.txt - OK, absolute path

STATUS=(subprocess.check_output("grep -a \'TEXT\' " + str(FILE_PATH.encode()), shell=True)).rstrip('\n')

I get this output in terminal
...: Command 'grep -a 'TEXT' b'/folder1/FILE.txt'' returned non-zero status 2

Any advice, please?

How to run Bash GREP command in Python on both binary/text file with variables (File path) ang store grep output into Variable in Python

Solution

You could try to use os.popen(), which should mimic and return the result you see when using the bash command:

import os
FILE_PATH = "/folder1/FILE.txt"
results = os.popen(f"grep -a 'TEXT' {FILE_PATH}").read()
print(results)

Answered By - user56700

Answer Checked By - Robin (WPSolving Admin)