Issue
I want to move files from directory 1 to directory 2, in that process if any file already exists in the destination folder it should instead move the file to directory 3.
I have create a script below but when ever file is skipped using -n parameter the result is true. Can someone let me know how to achieve this ?
#!/bin/bash
for file in dir1/*; do
mv -n $file /dir2
if [ $? != 0 ]; then
mv $file /dir3
fi
done
Solution
Suppose you have the following setup
mkdir dir{1,2,3}
touch dir1/test{1,2,3}
touch dir2/test2
The following code would move test1
and test3
to dir2
and test2
to dir3
out of dir1
for file in dir1/* ;
do
fname="${file##*/}" ;
if [ -f "dir2/$fname" ]; then
mv "$file" dir3/ ;
else
mv "$file" dir2/ ;
fi
done
Answered By - Dmitri Chubarov Answer Checked By - Willingham (WPSolving Volunteer)