[SOLVED] Function vs. Macro in CMake

Issue

The official document of CMake 2.8.12 says about macro

When it is invoked, the commands recorded in the macro are first modified by replacing formal parameters (${arg1}) with the arguments passed, and then invoked as normal commands.

and about function

When it is invoked, the commands recorded in the function are first modified by replacing formal parameters (${arg1}) with the arguments passed, and then invoked as normal commands.

Obviously, the two quotes are almost the same but it's confusing. Does parameter replacement behave the same in functions and macros?

Solution

I wrote a sample code below:

set(var "ABC")

macro(Moo arg)
  message("arg = ${arg}")
  set(arg "abc")
  message("# After change the value of arg.")
  message("arg = ${arg}")
endmacro()
message("=== Call macro ===")
Moo(${var})

function(Foo arg)
  message("arg = ${arg}")
  set(arg "abc")
  message("# After change the value of arg.")
  message("arg = ${arg}")
endfunction()
message("=== Call function ===")
Foo(${var})

and the output is:

=== Call macro ===
arg = ABC
# After change the value of arg.
arg = ABC
=== Call function ===
arg = ABC
# After change the value of arg.
arg = abc

So it seems arg is assigned the value of var when calling Foo and ${arg} is just string replaced with ${var} when calling Moo.

So I think the above two quotes are very easy to make one confused, although the official documents also said that:

Note that the parameters to a macro and values such as ARGN are not variables in the usual CMake sense. They are string replacements much like the C preprocessor would do with a macro. If you want true CMake variables and/or better CMake scope control you should look at the function command.

UPDATE (1/29/2021)

Add the following statement after the statement Moo(${var}) to make the difference between macro and function even more clear.

message(${arg})

This statement will print out abc.

Answered By - Yantao Xie

Answer Checked By - Cary Denson (WPSolving Admin)