[SOLVED] BASH scripting - unable to split string from grepped output and pass it one by one to a variable

Issue

I'm a beginner to bash scripting and been writing a script to check different log files and I'm bit stuck here.

clientlist=/path/to/logfile/which/consists/of/client/names 
#i will grep only the client name from the file which has multiple log lines 
clients=$(grep --color -i 'list of client assets:' $clientlist | cut -d":" -f1 )
echo "Clients : $clients"
#For example "Clients: Apple
#                      Samsung
#                      Nokia"
#number of clients may vary from time to time
assets=("$clients".log)
echo assets: "$assets"

The code above greps the client name from the log file and i'm trying to use the grepped client name (each) to construct a logfile with each client name.

The number of clients is indefinite and may vary from time to time.

The code I have returns the client name as a whole

assets: Apple
        Samsung
        Nokia.log

and I'm bit unsure of how to cut the string and pass it on one by one to return the assets which has .log for each client name. How can i do this ?

Apple.log
Samsung.log
Nokia.log

Solution

(Apologies if I have misunderstood the task)

Using awk

if your input file (I'll call it clients.txt) is:

Clients: Apple
         Samsung
         Nokia

The following awk step:

awk '{print $NF".log"}' clients.txt

outputs:

Apple.log
Samsung.log
Nokia.log

(You can pipe straight into awk and omit the file name if the pipe stream is as the file contents in the above example).

It is highly likely that a simple awk procedure can perform the entire task beginning with the 'clientlist' you process with grep (awk has all the functionality of grep built-in) but I'd need to know the structure of the origial file to extract the client names.

Answered By - Dave Pritlove

Answer Checked By - Katrina (WPSolving Volunteer)