[SOLVED] How to grep lines from a log file that have the current date?

Issue

I need to grep a log file with today's date, but the output is showing for more than today's date.

grep date +"20%y-%m-%d" /path/log/General.log | grep "EmpID#106496" /path/log/Genral.log

Output:

2013-06-19 14:47:05,996 - INFO  EmpID#106496 
2013-06-19 14:47:05,996 - INFO  EmpID#106496 
2013-06-21 00:01:24,915 - INFO  EmpID#106496 
2013-06-21 00:01:24,915 - INFO EmpID#106496  

Solution

Just use the date output as a pattern in grep:

$ grep "$(date +"%Y-%m-%d")" file
2013-06-21 00:01:24,915 - INFO   
2013-06-21 00:01:24,915 - INFO

That is, you need to enclose the date sentence to make it be processed. Also, note I used Y instead of your 20%y.

---

I am looking for a sepcific EmpID in the logs with current date.

Then pipe to another grep:

$ grep $(date +"%Y-%m-%d") file | grep "EmpID#106496"
2013-06-21 00:01:24,915 - INFO  EmpID#106496 
2013-06-21 00:01:24,915 - INFO EmpID#106496 

Answered By - fedorqui

Answer Checked By - Mary Flores (WPSolving Volunteer)