[SOLVED] How to get the first integer from all lines that match a pattern?

Issue

I have a file and I only want to find lines that have "here". In each of these lines there are multiple string and integer values (see example below). I only want the first integer of each line that matches the pattern.

I have created a solution that uses a bash script, but is there a simpler method I am missing. I was hoping something like grep -w here -Eo [0-9] file would work. However when I try that it expects anything that comes after "here" to be the file.

STEP 1 STAGE 1 here other info
foo
bar
STEP 2 STAGE 1 here other info
more
foo
bar
STEP 3 STAGE 1 here other info

For this file the desired output would be

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2
3

Solution

This simpler awk should work for you:

awk '/ here / {sub(/^[^0-9]+/, ""); print $1+0}' file

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Answered By - anubhava

Answer Checked By - Terry (WPSolving Volunteer)