[SOLVED] Grep output split for docker application

Issue

I learn about Docker for service hosting. I want to split the desired line somehow to obtain a desired token. In case the token corresponds to CONTAINER_ID, I would split the line in spaces and obtain the first token. I do not even know to start this shell pipe, but it seems useful for every SRE developer. :-)

I tried the command below:

docker ps -a | grep -w <image-name> | head -n1 | awk '{print $1;}'

The output below corresponds to command run docker ps -a.

CONTAINER ID   IMAGE                         COMMAND                  CREATED         STATUS         PORTS                                       NAMES
0e7e52667c2e   sappio-1                      "docker-entrypoint.s…"   3 minutes ago   Up 3 minutes   0.0.0.0:8080->8080/tcp, :::8080->8080/tcp   hardcore_panini
d9cd1a9d2c37   eclipse-mosquitto:2-openssl   "/docker-entrypoint.…"   2 weeks ago     Created                                                    cedalo_platform_mosquitto_1
96f65f3e8bd8   postgres:14.5                 "docker-entrypoint.s…"   3 weeks ago     Up 4 hours                                                 tests_db
bdb51a386349   nginxproxy/nginx-proxy        "/app/docker-entrypo…"   5 months ago    Created                                                    dreamy_bouman

Solution

FWIW, I often use the following few commands:

img=$(docker image ls | grep some_keyword | head -1 | awk '{print $3}') && echo "image is $img"

docker run -it $img

cont=$(docker ps | tail +2 | head -1 | awk '{print $1}') && echo "container is $cont"

The keyword would be something unique about the name of your image.

Answered By - Pierre D

Answer Checked By - Mary Flores (WPSolving Volunteer)