[SOLVED] Extract substring from a variables between two patterns in bash with special characters

Issue

I am trying to Extract substring from variables between two patterns in bash that as special characters inside the variable.

The variable:

MQ_URI=ssl://b-7dda5da6-59a5-4150-8e2f-16534985665-1.mq.us-east-1.amazonaws.com:61617?jms.prefetchPolicy.queuePrefetch=0

What I've tried so far:

echo "$MQ_URI" | sed -E 's/.*ssl:// (.*) :61617.*/\1/'

Got me this in response:

sed: -e expression #1, char 12: unknown option to `s'

Also tried with grep:

echo $MQ_URI | grep -o -P '(?<=ssl://).*(?=:61617jms.prefetchPolicy.queuePrefetch=0)

The output I need is everything between: "ssl://" and ":61617?jms.prefetchPolicy.queuePrefetch=0"

which is : "b-7dda5da6-59a5-4150-8e2f-16534985665-1.mq.us-east-1.amazonaws.com"

Solution

Using bash

$ mq_uri=${mq_uri##*/}
$ mq_uri=${mq_uri//:*}
$ echo "$mq_uri"
b-7dda5da6-59a5-4150-8e2f-16534985665-1.mq.us-east-1.amazonaws.com

sed

$ sed -E 's~[^-]*/([^?]*):.*~\1~' <<< "$mq_uri" 
b-7dda5da6-59a5-4150-8e2f-16534985665-1.mq.us-east-1.amazonaws.com

grep

$ grep -Po '[^-]*/\K[^:]*' <<< "$mq_uri" 
b-7dda5da6-59a5-4150-8e2f-16534985665-1.mq.us-east-1.amazonaws.com

awk

$ awk -F'[/:]' '{print $4}' <<< "$mq_uri" 
b-7dda5da6-59a5-4150-8e2f-16534985665-1.mq.us-east-1.amazonaws.com

Answered By - HatLess

Answer Checked By - Pedro (WPSolving Volunteer)