[SOLVED] delete files in a sequence and count in shell

Issue

In a specific Unix directory on a server. I would like to list down files and delete them in a sequence one by one. Below program is showing errors in for loop. Can anybody help to make it work?

#!/bin/sh
address=/apps/applications/jboss-as/servers/scripts/
files=$(ls $address)
echo Below files will be deleted-
echo $files

k=0
for i in "$files" do {
 rm $i       
 k++
}
done

echo ${k} files are deleted.

Solution

I fixed the script, but as others pointed out, you may want to use something other than the ls, but I left it in. There were other syntax errors as well. Here it is:

#!/bin/bash

address=/apps/applications/jboss-as/servers/scripts/
files=("$address"/*)

echo Below files will be deleted-
echo "${files[@]}"

k=0
for i in "${files[@]}" ; do
 echo "removing $i ..."
 rm "$i"
 ((k++))
done

echo ${k} files are deleted.

---

UPDATE:

Since you're still having trouble, you might add declare -a files just above the files=( "$address"/* ). It might fix the problem for you (but, the script runs fine without it here), and it doesn't hurt anything when I run the script here with it. So, either way ...

Answered By - Craig Estey

Answer Checked By - Dawn Plyler (WPSolving Volunteer)