Issue
How can I list every occurrence of a regex in a file, where one line can contain the regex multiple times?
Example:
XXXXXXXXXX FOO3 XXXX FOO4 XXX
XXX FOO2 XXXX FOO9 XXXXXX FOO5
The result should be:
FOO3
FOO4
FOO2
FOO9
FOO5
The regex would be /FOO./ in this case.
Grep will return every line that matches at least one time. But that's not what I want.
Solution
Have you tried the -o option: (grep man page)
-o, --only-matching Show only the part of a matching line that matches PATTERN.
Answered By - Sam Answer Checked By - Dawn Plyler (WPSolving Volunteer)