[SOLVED] Call a shell script method with parameter using nohup

Issue

/bin/scripts/first.ksh

#!/bin/bash
start(){
   first="$1";
   echo "arg is $first"
}

/bin/scripts/second.sh

#!/bin/bash
nohup sh /bin/scripts/first.ksh start arg1 > nohup_log 2>&1 &

The argument is not picked up. What is the correct way to pass argument in the second script

Solution

If you pass parameters, you have to use them somehow. One possibility is technically do write your script as

start(){
 first="$1";
 echo "arg is $first"
}

"$@"

The last line would - in your case - expand to start arg1 and therefore call your function. However it is risky to do this: Since the first parameter to your script (i.e. start) is treated as a command to be executed, the user of the script could inject any code via the parameter. This is a serious security hole.

I would at least verify the first parameter somehow, or redesign your script completely. For instance, it is unclear why you define a function, if the script isn't doing anything else than calling this function.

Answered By - user1934428

Answer Checked By - Terry (WPSolving Volunteer)