[SOLVED] Sed version extract

Issue

I am trying to extract the version number from a string. I am unable to find the exact regex to find what I need.

For eg -

1012-EPS-Test-OF-Something-1.3 

I need sed to only extract 1.3 from the above line.

I have tried quite a few things until now something like but it is clearly not working out

sed 's/[^0-9.0-9]*//')

Solution

With your shown samples, easiest way could be. Simply print value of shell variable into awk program as input and then setting field separator as - and printing the last field value in it.

echo "$string" | awk -F'-' '{print $NF}'

2nd solution: In case you could have anything else also apart from version number in last field of your value(where - is field delimiter) then use match function of awk.

echo "$var" | 
awk -F'-' 'match($NF,/[0-9]+(\.[0-9]+)*/){print substr($NF,RSTART,RLENGTH)}'

3rd solution: Using GNU grep try following once. Using \K option for GNU grep here. This will match everything till - and then mentioning \K will forget OR wouldn't consider that matched value for printing and will print all further matched value(with further mentioned regex).

echo "$var" | grep -oP '.*-\K\d+(\.\d+)*'

Answered By - RavinderSingh13

Answer Checked By - Cary Denson (WPSolving Admin)