[SOLVED] Sed replacement in bash

Issue

I´m wondering how can i just replace this variable easily in BASH:

VARIABLE1="VALUE2=somestring2 VALUE3=TRUE"

I need just to change VALUE2=somestring2 (which is just part of the string) with a new value that replaces it:

i am just using this:

VARIABLE1="${VARIABLE1//VALUE2=[a-z0-9-]*/}VALUE2=${VALUE2}"

where VALUE2=${VALUE2} is a new value that i specify in some line.

but there are two problems here:

1- the line where i overwrite the VALUE2=somestring2 deletes VALUE3=TRUE from VARIABLE1

2- looks like after overwrite VALUE2, it puts a "space" at the beginning of "VALUE2=somestring2"

echo $VARIABLE1 " VALUE2=somestring2"

Any way to fix this?

Solution

Try

shopt -s extglob
VARIABLE1=${VARIABLE1/VALUE2=*([a-z0-9-])/VALUE2=$VALUE2}

• shopt -s extglob turns on extended globbing in Bash. That enables (among other things) the built-in substitution mechanism to use a form of regular expressions (*([a-z0-9-]) here). See the extglob section in glob - Greg's Wiki
• Note that ALL_UPPERCASE variable names like VARIABLE1 are potentially dangerous. They can clash with the many special ALL_UPPERCASE variables that exist. See Correct Bash and shell script variable capitalization. Names like variable1 are generally safe.

Answered By - pjh

Answer Checked By - Marilyn (WPSolving Volunteer)