[SOLVED] Printing arrays are not working in shell script

Issue

I am kind of new in shell scripting and trying to learn arrays. I declared array value but when I am trying to print that array it is giving me an error(bad substitution). I am pasting the code below, please suggest to me what is wrong here-

➜  ~ cat test.sh
#!/bin/bash

array=['foo','bar','a','b']
echo 1
echo "${array[0]}"
➜  ~ sh test.sh
1
test.sh: 5: Bad substitution

Thanks in advance.

Solution

Depending on the system you're using sh might be not be Bash and it's not Bash on yours, it can be dash for example. Run your script with Bash:

$ bash arr.sh
1
[foo,bar,a,b]

Or set an executable bit and call the script without providing the name of the interpreter since you already have the shebang:

$ chmod +x test.sh
$ ./test.sh
1
[foo,bar,a,b]

Answered By - Arkadiusz Drabczyk

Answer Checked By - Clifford M. (WPSolving Volunteer)