[SOLVED] How to remove a single command from bash autocomplete

Issue

How do I remove a single "command" from Bash's auto complete command suggestions? I'm asking about the very first argument, the command, in auto complete, not asking "href="https://unix.stackexchange.com/questions/96534/disable-bash-autocompletion-for-a-specific-command-only">How to disable bash autocomplete for the arguments of a specific command"

For example, if I have the command ls and the system path also finds ls_not_the_one_I_want_ever, and I type ls and then press tab, I want a way to have removed ls_not_the_one_I_want_ever from every being a viable option.

I think this might be related to the compgen -c list, as this seems to be the list of commands available.

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Background: WSL on Windows is putting all the .dll files on my path, in addition to the .exe files that should be there, and so I have many dlls I would like to remove in my bash environment, but I'm unsure how to proceed.

Solution

Bash 5.0's complete command added a new -I option for this.

According to man bash —

• complete -pr [-DEI] [name ...]

  [...] The -I option indicates that other supplied options and actions should apply to completion on the initial non-assignment word on the line, or after a command delimiter such as ; or |, which is usually command name completion. [...]

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Example:

function _comp_commands()
{
    local cur=$2

    if [[ $cur == ls* ]]; then
        COMPREPLY=( $(compgen -c "$cur" | grep -v ls_not_wanted) )
    fi
}

complete -o bashdefault -I -F _comp_commands

Answered By - pynexj

Answer Checked By - Senaida (WPSolving Volunteer)