[SOLVED] How to apply multiple parameter expansion in BASH for a single output?

Issue

files=("Benjamin Johnson" "Bastin Johnson" "Bagio Johnson")

( IFS=','; echo "${files[*]/#/Mr.}"; echo "${files[*]/ /_}" )

Expected Result Mr.Benjamin_Johnson,Mr.Bastin_Johnson,Mr.Bagio_Johnson

Output result:

Mr.Benjamin Johnson,Mr.Bagio Johnson,Mr.Bastin Johnson

Benjamin_Johnson,Bagio_Johnson,Bastin_Johnson

Solution

Just use an intermediate array.

( IFS=','; files=("${files[@]/#/Mr.}"); echo "${files[*]/ /_}" )

Answered By - KamilCuk

Answer Checked By - Katrina (WPSolving Volunteer)