[SOLVED] grep prints random character from bash script to the output file

Issue

I am not too used to bash script so kindly bear with me The following code prints the array in the output file that grep creates. what is it that I am missing?

ids=(eebab078-6076-4ed7-91bb-624313865380)
ids+=(cd0b1f5d-2c86-43d4-ad86-b8beef7db4c9)

echo 'start processing'
for id in ${ids[@]}; do
    echo 'processing' $id
    grep -rih --exclude-dir={reprocessing} $id >> '../result-test.dat' 
done
echo 'end processing'

The output looks like this. I am only expecting the search results not the extra ids which is part of the array.

search results 
ids=(eebab078-6076-4ed7-91bb-624313865380)
ids+=(cd0b1f5d-2c86-43d4-ad86-b8beef7db4c9)

Any help will be greatly appreciated

Solution

Thanks very much @William Pursell

your answer helped me move in the right direction

used this script that worked

ids=(eebab078-6076-4ed7-91bb-624313865380)
ids+=(cd0b1f5d-2c86-43d4-ad86-b8beef7db4c9)
echo 'start processing'
for id in ${ids[@]}; do
    echo 'processing' $id
    grep -Rih --exclude-dir={reprocessing} --exclude=\*.sh $id >> '../result-test.dat' 
done
echo 'end processing'

Answered By - user1131926

Answer Checked By - Mary Flores (WPSolving Volunteer)