[SOLVED] FileCount on Unix

Issue

I am trying to find the number of files in a directory. I am using the ls command. Based on the Number of Files, I need to display the count and a message. Script doesn't provide the desired output. Any assistance will be appreciated.

#!/bin/sh

FILECOUNT = $(ls /opt/report/ | grep *.ZIP_30 | wc -l);

if [ $FILECOUNT -gt "0" ]; then
      echo "Statistic.filecount: $FILECOUNT";
      echo "Message.filecount: Normal";
else
      echo "Statistic.filecount: $FILECOUNT";
      echo "Message.filecount: Warning";
fi;

exit 0;

Solution

You have a syntax error.

No spaces allowed around = in shell, so:

filecount=$(grep -c ZIP_30 /opt/report/*)

Answered By - Gilles Quenot

Answer Checked By - Robin (WPSolving Admin)