Issue
I have a Makefile for a C program that has the declaration
CC?=gcc
Changing it to
CC?=g++
does NOT make it compile with g++. Changing it to
CC=g++
DOES make it use g++.
So I wonder what the ?= operator does? My guess is that it looks at a environment variable to decide which compiler to use and if it's not set then use gcc? Anyone who can clear this up?
Solution
From http://www.gnu.org/software/make/manual/make.html:
There is another assignment operator for variables, `?='. This is called a conditional variable assignment operator, because it only has an effect if the variable is not yet defined. This statement:
FOO ?= bar
is exactly equivalent to this (see The origin Function):
ifeq ($(origin FOO), undefined) FOO = bar endif
Probably CC
is already defined as gcc
, so CC ?= g++
won't override the existing gcc
.
Answered By - kennytm Answer Checked By - Mildred Charles (WPSolving Admin)