Issue
I have a date in the format of 201908270700
but need to change it to yyyy/mm/dd hh:mm
, when googling I find lots of solutions to do this with the macOS command line, but not many for linux, at least not a simple solution.
On macOS you can do date -jf "%Y%m%d%H%M" "201908270700" "+%Y/%m/%d %H:%M"
and it'll return 2019/08/27 07:00
, but looking at the GNU date man page, there is no equivalent option on Linux, or is there?
Solution
With the date in a variable, it's easy to format into a form the GNU coreutils date(1)
understands:
$ dt=201908270700
$ date -d"${dt:0:8} ${dt:8:4}" "+%Y/%m/%d %H:%M"
2019/08/27 07:00
This splits the date and time up into separate elements, which can then be parsed according to the rules for pure numbers in the coreutils documentation.
Answered By - Shawn Answer Checked By - Clifford M. (WPSolving Volunteer)