Issue
I have a file of IP and every line have two or three comma separated IP like -
ip x 171.48.179.64, 194.88.105.83, 10.121.15.191
ip x 122.176.17.76, 194.88.105.83, 10.121.15.191
ip x 223.179.196.169, 10.121.15.135
ip x 157.41.161.64, 10.121.15.135
ip x 49.14.160.119, 10.121.15.191
ip x 157.41.230.108, 10.121.15.191
ip x 101.208.189.88, 194.88.105.83, 10.121.15.191
ip x 180.215.137.150, 194.88.105.83, 10.121.15.191
ip x 157.41.161.64, 10.121.15.191
ip x 157.41.161.64, 10.121.15.191
So I want to grep the lines which contains two comma (three IPs) like -
ip x 171.48.179.64, 194.88.105.83, 10.121.15.191
ip x 122.176.17.76, 194.88.105.83, 10.121.15.191
ip x 101.208.189.88, 194.88.105.83, 10.121.15.191
ip x 180.215.137.150, 194.88.105.83, 10.121.15.191
I searched a lot but did't get any specific answer, please help me.
Solution
You can use awk:
awk -F, 'NF==3' file
-F, sets the delimiter to ,. NF is a special variable which contains the number of fields. If the condition NF==3 is met awk will print the current line.
With (e)grep it would be something like this:
grep -E '^([^,]+,){2}[^,]+$' file
I would personally use awk because it is much more readable.
Answered By - hek2mgl Answer Checked By - Robin (WPSolving Admin)