[SOLVED] How to crop text after pattern in bash

Issue

If the text is

aaaa
bbbb
cccc
====
dddd

I want dddd as the result

If the text is

aaaa
====
bbbb
cccc
dddd

I want

bbbb
cccc
dddd

as the result.

I'm trying something like awk '{print $1}' | sed '/.*\n=*$/d' but it seems like sed can only delete a line.

Solution

You can try something like

n=$(grep -n "^=*$" $1 | awk -F: '{print $1}')
let n+=1
tail +$n $1

Answered By - Yuri Ginsburg

Answer Checked By - David Marino (WPSolving Volunteer)