Issue
Suppose I have a file as follows (a sorted, unique list of integers, one per line):
1
3
4
5
8
9
10
I would like the following output (i.e. the missing integers in the list):
2
6
7
How can I accomplish this within a bash terminal (using awk or a similar solution, preferably a one-liner)?
Solution
Using awk you can do this:
awk '{for(i=p+1; i<$1; i++) print i} {p=$1}' file
2
6
7
Answered By - anubhava Answer Checked By - Marilyn (WPSolving Volunteer)
