[SOLVED] Grep returns no such file or directory when using multiple flags

Issue

I am a beginner of bash script. I just started to write a script where it checks the contents of b.txt can all be found in a.txt. (line by line preferably). My code is as following:
grep -Ffw b.txt a.txt

As you can see, I want to do fixed string instead of REGEX, I want to check everything from the b.txt file, because there are some strings inside the b.txt and I want to check if all of them exist in a.txt. And I also want to match the whole word only of course. So these are the requirements, however when I run this command it returns me an error says:
grep: w: No such file or directory

I am thinking that maybe there are some limitations of the flags in bash? Sorry I am not really familiar with the language, didn't read much about the MAN page etc. If anyone could help me to solve the puzzle it would be appreciated :) In addition, i think if possible I would like to add a -q to surpress the output when there is a match also, right now I didn't add it in the example since it couldn't make it through with 3 flags even. So can anyone give me some hints here? Thanks in advance!

Solution

Hereby some explanation from the manpage:

OPTIONS
   Generic Program Information
   ...
      -F, --fixed-strings
              Interpret PATTERNS as fixed strings, ...
      -f FILE, --file=FILE
              Obtain patterns from FILE, ...
      -w, --word-regexp
              Select only those lines ...

As you can see, the options -F and -w are indicated ending immediately (hence the comma in -F, and -w,), but the -f switch is followed by FILE, with means they belong together.

I you want to preserve the order Ffw, that's possible, but then you need to do something like:

grep -Ff b.txt -w a.txt

Answered By - Dominique

Answer Checked By - Mary Flores (WPSolving Volunteer)