Issue
I do the following in order to get all WORD in file but not in lines that start with "//"
grep -v "//" file | grep WORD
Can I get some other elegant suggestion to find all occurrences of WORD
in the file except lines that begin with //
?
Remark: "//" does not necessarily exist at the beginning of the line; there could be some spaces before "//".
For example
// WORD
AA WORD
// ss WORD
Solution
grep -v "//" file | grep WORD
This will also exclude any lines with "//" after WORD, such as:
WORD // This line here
A better approach with GNU Grep would be:
grep -v '^[[:space:]]*//' file | grep 'WORD'
...which would first filter out any lines beginning with zero-or-more spaces and a comment string.
Trying to put these two conditions into a single regular expression is probably not more elegant.
Answered By - Johnsyweb Answer Checked By - Cary Denson (WPSolving Admin)