Issue
I have logs in this format. I'm looking to get logs only that has count more than 5000.
Matching pattern should be Count [value greater than 5000]
INFO 56783 Count [5987]
INFO 67988 Count [4986]
INFO 27679 Count [9865]
In the above example, the output should be only
INFO 56783 Count [5987]
I'm using in the following format
sudo cat <path to log> | grep 'Count [5[0-9][0-9][0-9]]'
Any ideas what is missing here
Solution
You may use this grep:
grep -E 'Count \[[5-9][0-9]{3,}\]' file
INFO Count [5987]
INFO Count [9865]
Here regex pattern is \[[5-9][0-9]{3,}\] that matches a:
\[: Match opening[[5-9]: Match digits between5to9[0-9]{3,}: Match 3 or more digits\]: Match closing]
This will match 5000 or an integer greater than 5000 inside [...].
However, you should be using awk for this job to get most flexibility:
awk '$2 == "Count" && gsub(/[][]/, "", $3) && $3+0 > 5000' file
INFO Count 5987
INFO Count 9865
Answered By - anubhava Answer Checked By - Marie Seifert (WPSolving Admin)