[SOLVED] Capture word after pattern with slash

Issue

I want to extract word1 from:

something /CLIENT_LOGIN:word1 something else

I would like to extract the first word after matching pattern /CLIENT_LOGIN:.

Without the slash, something like this works:

A=something /CLIENT_LOGIN:word1 something else
B=$(echo $A | awk '$1 == "CLIENT_LOGIN" { print $2 }' FS=":")

With the slash though, I can't get it working (I tried putting / and \/ in front of CLIENT_LOGIN). I don't care getting it done with awk, grep, sed, ...

Solution

Using sed:

s='=something /CLIENT_LOGIN:word1 something else'
sed -E 's~.* /CLIENT_LOGIN:([^[:blank:]]+).*~\1~' <<< "$s"

word1

Details:

• We use ~ as regex delimiter in sed
• /CLIENT_LOGIN:([^[:blank:]]+) matches /CLIENT_LOGIN: followed by 1+ non-whitespace characters that is captured in group #1
• .* on both sides matches text before and after our match
• \1 is used in substitution to put 1st group's captured value back in output

Answered By - anubhava

Answer Checked By - Senaida (WPSolving Volunteer)