[SOLVED] numbers as command-line arguments and prints the count

Issue

I want to take numbers as command-line arguments and prints the count of numbers that end with 0, 1, 2, etc. up to 5.

Example:

bash test.sh 12 14 12 15 14

Expected Output:

Digit_ends_with   count
0                  0
1                  0
2                  2
3                  0
4                  2
5                  1

Mt Attempt:

read -a integers                                                                                                                                                                                                                                for i in ${integers[@]}                                                                                                 do                                                                                                                              if [[ grep -o '[0-9]' $i ]]                                                                                                     count=$(grep -c $i)                                                                                                     if [ "$count" -ge "0" ]                                                                                                 then 
echo "Digit_ends_with" $i                                                                                                                           echo -e "Count ""$count"                                                                                                fi                                                                                                              fi                                                                                                              done 

But this is not working. How I can achieve this requirement?

Solution

Would you please try the following:

#!/bin/bash

for i in "$@"; do                               # loop over arguments
    (( count[i % 10]++ ))                       # index with the modulo 10
done

printf "%s %s\n" "Digit_ends_with" "count"      # header line
for (( i = 0; i < 6; i++ )); do                 # loop between 0 and 5
    printf "%d\t\t%d\n" "$i" "${count[$i]}"     # print the counts
done

Result of ./test.sh 12 14 12 15 14:

Digit_ends_with count
0               0
1               0
2               2
3               0
4               2
5               1

Answered By - tshiono

Answer Checked By - Katrina (WPSolving Volunteer)