Issue
I'm using wikipedia api to scrape images from api its returning data in json form in which the image Url is like this "https://upload.wikimedia.org/wikipedia/en/f/f7/Canada%27s_Aviation_Hall_of_Fame_logo.jpg" the Url that is same for all images is "https://upload.wikimedia.org/wikipedia/en/" The Php code is as follows:
<form action="" method="get">
<input type="text" name="search">
<input type="submit" value="Search">
</form>
<?php
if(@$_GET['search']){
$api_url="https://en.wikipedia.org/w/api.php?action=query&format=json&list=allimages&aifrom=".ucwords($_GET['search'])."&ailimit=500";
$api_url=str_replace('', '%20', $api_url);
$curl=curl_init();
curl_setopt($curl, CURLOPT_URL, $api_url);
curl_setopt($curl,CURLOPT_RETURNTRANSFER, true);
$output=curl_exec($curl);
curl_close($curl);
preg_match_all('!//upload.wikimedia.org/wikipedia/en/!', $output, $data);
echo '<pre>';
foreach ($data[0] as $list) {
echo "<img src='$list'/>";
# code...
}
}
?>
How can I get the remaining part of the url correctly?
Solution
You need to decode it using json_decode and get the url image link
function get_wiki_image( $search, $limit) {
$streamContext = array(
"ssl" => array(
"verify_peer" => false,
"verify_peer_name" => false,
),
);
$url = 'https://en.wikipedia.org/w/';
$url .= '/api.php?action=query&format=json&list=allimages&aifrom=' . $search . '&ailimit=' . $limit;
$context = stream_context_create($streamContext);
if(FALSE === ($content = @file_get_contents($url, false,$context)) ) {
return false;
} else {
$data = json_decode($content,true);
$ret = array();
foreach($data['query']['allimages'] as $img) {
$ret[] = $img['url'];
}
return $ret;
}
}
$search = ucwords($_GET['search']);
$images = get_wiki_image($search,500);
foreach($images as $img) {
echo "<img src='{$img}'>";
}
Answered By - Jerson Answer Checked By - Dawn Plyler (WPSolving Volunteer)