[SOLVED] Excluding selective file from run inside bash shell script

Issue

I want to run below gnuplot command to generate graph from gpl file.

gnuplot gplfile0.gpl 
gnuplot gplfile1.gpl 
gnuplot gplfile2.gpl 
gnuplot gplfile3.gpl 
gnuplot gplfile4.gpl 
gnuplot gplfile5.gpl 
gnuplot gplfile6.gpl 
..
..
..
..

I have a parent gplfile.gpl which help to generate all require gplfile*.gpl with unique content. I don't want to remove or move or delete parent file form given folder.

I have written a bash shell script to run above commands.

run_script.sh :

#!/bin/bash

echo "Generating the images using gnu plot"

date 

shopt -s extglob
rm -rf *.png

for f in *gpl
do
    gnuplot $f
done

I am able to generate output from all gplfile*.gpl file. But I want to exclude parent gplfile.gpl from running .

How I can exclude running parent gplfile.gpl file from the bash shell script.

Is there any command in the bash shell script to exclude the specific file from run.

Solution

Since you have extglob on then.

for file in !(gplfile).gpl; do echo gnuplot "$file"; done

Answered By - Jetchisel

Answer Checked By - Candace Johnson (WPSolving Volunteer)