[SOLVED] Different functions from different scripts in bash

Issue

I want to make a script which calls functions from different scripts, but once I've called another script, every single internal function doesn't recognize it.

I have no idea how to go on. I tried to erase the call, but once I erase the call to another script, obviously, these functions aren't working.

#!/bin/bash

. generalFunct
is_stora_mounted="true"
counter=0
user1000=$(cut -d: -f1,3 /etc/passwd | egrep ':[0-9]{4}$' | cut -d: -f1)

doCheckSudo
doDisableCdrom
doCheckOS
doAddProgramSources
doInstallOtherDependency
doAddSources
doAddAnsibleSources
doInstallPrinter
doInstallSenior

doAddAnsibleSources() {
    bla bla bla bla
}



doInstallSenior() {

    bla bla bla bla bla bla

}
doInstallVPN
doUpgradeAndUpdate
doInstallWifiDriver
doAddCertificates
doDownloadDockerImages

[BLA BLA BLA IT'S TO KEEP THE PRIVACY ON MY WORKPLACE]

doAddAnsibleSources and doInstallSenior are the functions which are internal.

I expected to work, but it says that it can't find the order (refering to the function title)

Solution

The problem is that the functions are defined after they are called. Move them to the top of the script and try again.

doAddAnsibleSources() {
 ...
}

doAddAnsibleSources

Instead of:

doAddAnsibleSources

doAddAnsibleSources() {
 ...
}

This is required as bash is interpreted environment and does no preprocessing, just executes line after line. When reading a file in this way, it tries to execute function it hasn't seen yet.

Answered By - Šimon Kocúrek

Answer Checked By - Dawn Plyler (WPSolving Volunteer)