[SOLVED] Delete directory based on date

Issue

I am writing zsh script in which I have to get the date of 90th previous day from current date i.e I have to subtract 90 days from current date. Then I have to check the folders which have different dates as their names. I have to compare the directory date with the subtracted date and if the result is greater than the subtracted date, I have to delete the directory.

For example:

Let us say the current_date = 20131130 (yyyymmdd)

subtracted_date=current_date - 90 days

lets say there is a folder 20130621

Now this folder name should be compare with the subtracted date. If greater than subtracted_date then i have to delete the directory.

Solution

You can use the date command to find the date 90 days earlier to the current one. The following script should give you a list of directories that need to be deleted:

del=$(date --date="90 days ago" +%Y%m%d)
for i in `find . -type d -name "2*"`; do
  (($del > $(basename $i))) && echo "delete $i" || echo "dont delete $i"
done

To perform the actual deletion of directories, you can replace the third line with the following:

  (($del > $(basename $i)))  && rm -rf $i

For example, if your current directory contains the following folders:

$ ls -1F
20120102/
20130104/
20130302/
20130402/
20130502/
20130602/
20130702/

Executing the above script would tell:

$ bash cleanup
delete ./20130302
delete ./20130104
delete ./20120102
delete ./20130402
dont delete ./20130702
dont delete ./20130502
dont delete ./20130602

Answered By - devnull

Answer Checked By - Katrina (WPSolving Volunteer)