[SOLVED] Regex that matches whatever comes after a pattern

Issue

Important: I have already looked up similar questions on Stackoverflow and elsewhere and I couldnt find a solution.

I'm trying to make a regular expression that matches whatever comes after this pattern (the pattern itself excluded)

[-a-zA-Z0-9]+\/[-\._a-zA-Z0-9]+

I tried using ^ as a NOT operator like so:

[^([-a-zA-Z0-9]+\/[-\._a-zA-Z0-9]+)]

But it throws a syntax error: Unmatched '('. Seems like it associates the first ] with the first [ instead of with the second. How to fix this?

I also tried doing a Positive Lookbehind like so:

(?<=([-a-zA-Z0-9]+\/[-\._a-zA-Z0-9]+).*)

But it's not working.

What am I doing wrong?

Solution

You can capture all that follows the match in group 1, and use group 1 in the replacement.

[-a-zA-Z0-9]+\/[-._a-zA-Z0-9]+(.+)

The contents of file to test with:

hello/w0rld/blbalba0
hel-lo/wor_ld?q=0
hello/w0rld)/blbalba0
hel-lo/wor_&ld?q=0(

As you mention in the comments that you want to use sed:

sed -E 's/[-a-zA-Z0-9]+\/[-._a-zA-Z0-9]+(.+)/\1/' file

Output:

/blbalba0
?q=0
)/blbalba0
&ld?q=0(

Answered By - The fourth bird

Answer Checked By - Pedro (WPSolving Volunteer)