[SOLVED] live output from subprocess command

Issue

I'm using a python script as a driver for a hydrodynamics code. When it comes time to run the simulation, I use subprocess.Popen to run the code, collect the output from stdout and stderr into a subprocess.PIPE --- then I can print (and save to a log-file) the output information, and check for any errors. The problem is, I have no idea how the code is progressing. If I run it directly from the command line, it gives me output about what iteration its at, what time, what the next time-step is, etc.

Is there a way to both store the output (for logging and error checking), and also produce a live-streaming output?

The relevant section of my code:

ret_val = subprocess.Popen( run_command, stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True )
output, errors = ret_val.communicate()
log_file.write(output)
print output
if( ret_val.returncode ):
    print "RUN failed\n\n%s\n\n" % (errors)
    success = False

if( errors ): log_file.write("\n\n%s\n\n" % errors)

Originally I was piping the run_command through tee so that a copy went directly to the log-file, and the stream still output directly to the terminal -- but that way I can't store any errors (to my knowlege).

---

My temporary solution so far:

ret_val = subprocess.Popen( run_command, stdout=log_file, stderr=subprocess.PIPE, shell=True )
while not ret_val.poll():
    log_file.flush()

then, in another terminal, run tail -f log.txt (s.t. log_file = 'log.txt').

Solution

TLDR for Python 3:

import subprocess
import sys
with open('test.log', 'wb') as f: 
    process = subprocess.Popen(your_command, stdout=subprocess.PIPE)
    for c in iter(lambda: process.stdout.read(1), b''): 
        sys.stdout.buffer.write(c)
        f.buffer.write(c)

---

You have two ways of doing this, either by creating an iterator from the read or readline functions and do:

import subprocess
import sys
with open('test.log', 'w') as f:  # replace 'w' with 'wb' for Python 3
    process = subprocess.Popen(your_command, stdout=subprocess.PIPE)
    for c in iter(lambda: process.stdout.read(1), ''):  # replace '' with b'' for Python 3
        sys.stdout.write(c)
        f.write(c)

or

import subprocess
import sys
with open('test.log', 'w') as f:  # replace 'w' with 'wb' for Python 3
    process = subprocess.Popen(your_command, stdout=subprocess.PIPE)
    for line in iter(process.stdout.readline, ''):  # replace '' with b'' for Python 3
        sys.stdout.write(line)
        f.write(line)

Or you can create a reader and a writer file. Pass the writer to the Popen and read from the reader

import io
import time
import subprocess
import sys

filename = 'test.log'
with io.open(filename, 'wb') as writer, io.open(filename, 'rb', 1) as reader:
    process = subprocess.Popen(command, stdout=writer)
    while process.poll() is None:
        sys.stdout.write(reader.read())
        time.sleep(0.5)
    # Read the remaining
    sys.stdout.write(reader.read())

This way you will have the data written in the test.log as well as on the standard output.

The only advantage of the file approach is that your code doesn't block. So you can do whatever you want in the meantime and read whenever you want from the reader in a non-blocking way. When you use PIPE, read and readline functions will block until either one character is written to the pipe or a line is written to the pipe respectively.

Answered By - Viktor Kerkez