[SOLVED] How to match and cut the string with different conditions using sed?

Issue

I want to grep the string which comes after WORK= and ignore if there comes paranthesis after that string .

The text looks like this :

//INALL TYPE=GH,WORK=HU.ET.ET(IO)
//INA2 WORK=HU.TY.TY(OP),TYPE=KK
//OOPE2 TYPE=KO,WORK=TEXT.LO1.LO2,TEXT
//OOP2 TYPE=KO,WORK=TEST1.TEST2
//H1 WORK=OP.TEE.GHU,TYPE=IU

So, desirable output should print only :

TEXT.L01.L02
TEST1.TEST2
OP.TEE.GHU

So far , I could just match and cut before WORK= but could not remove WORK= itself:

sed -E 's/(.*)(WORK=.*)/\2/'

I am not sure how to continue . Can anyone help please ?

Solution

You can use

sed -n '/WORK=.*([^()]*)/!s/.*WORK=\([^,]*\).*/\1/p' file > newfile

Details:

• -n - suppresses the default line output
• /WORK=.*([^()]*)/! - if a line contains a WORK= followed with any text and then a (...) substring skips it
• s/.*WORK=\([^,]*\).*/\1/p - else, takes the line and removes all up to and including WORK=, and then captures into Group 1 any zero or more chars other than a comma, and then remove the rest of the line; p prints the result.

See the sed demo:

s='//INALL TYPE=GH,WORK=HU.ET.ET(IO)
//INA2 WORK=HU.TY.TY(OP),TYPE=KK
//OOPE2 TYPE=KO,WORK=TEXT.LO1.LO2,TEXT
//OOP2 TYPE=KO,WORK=TEST1.TEST2
//H1 WORK=OP.TEE.GHU,TYPE=IU'
sed -n '/WORK=.*([^()]*)/!s/.*WORK=\([^,]*\).*/\1/p' <<< "$s"

Output:

TEXT.LO1.LO2
TEST1.TEST2
OP.TEE.GHU

Answered By - Wiktor Stribiżew