Issue
I use the following bash script to copy only files of certain extension(in this case *.sh), however it still copies over all the files. what's wrong?
from=$1 to=$2 rsync -zarv --include="*.sh" $from $to
Solution
I think --include
is used to include a subset of files that are otherwise excluded by --exclude
, rather than including only those files.
In other words: you have to think about include meaning don't exclude.
Try instead:
rsync -zarv --include "*/" --exclude="*" --include="*.sh" "$from" "$to"
For rsync version 3.0.6 or higher, the order needs to be modified as follows (see comments):
rsync -zarv --include="*/" --include="*.sh" --exclude="*" "$from" "$to"
Adding the -m
flag will avoid creating empty directory structures in the destination. Tested in version 3.1.2.
So if we only want *.sh files we have to exclude all files --exclude="*"
, include all directories --include="*/"
and include all *.sh files --include="*.sh"
.
You can find some good examples in the section Include/Exclude Pattern Rules of the man page
Answered By - chepner